3x/x-4-6/x^2-7x+12=2x/x-3

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Solution for 3x/x-4-6/x^2-7x+12=2x/x-3 equation: 



3x/x-4-6/x^2-7x+12=2x/x-3

We move all terms to the left:

3x/x-4-6/x^2-7x+12-(2x/x-3)=0



Domain of the equation: x!=0

x∈R





Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: x-3)!=0

x∈R



We add all the numbers together, and all the variables

-7x+3x/x-6/x^2-(2x/x-3)+8=0

We get rid of parentheses

-7x+3x/x-6/x^2-2x/x+3+8=0

We calculate fractions

We do not support expression: x^3

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